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11x^2+15/11=8x
We move all terms to the left:
11x^2+15/11-(8x)=0
We multiply all the terms by the denominator
11x^2*11-8x*11+15=0
Wy multiply elements
121x^2-88x+15=0
a = 121; b = -88; c = +15;
Δ = b2-4ac
Δ = -882-4·121·15
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-88)-22}{2*121}=\frac{66}{242} =3/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-88)+22}{2*121}=\frac{110}{242} =5/11 $
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